document.write( "Question 121939: I need help with the following problems:\r
\n" ); document.write( "\n" ); document.write( "y = 2x + 6
\n" ); document.write( "y = -x -3\r
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\n" ); document.write( "\n" ); document.write( "y - 3x = 9
\n" ); document.write( "2y + x = 4\r
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\n" ); document.write( "\n" ); document.write( "y + 4 = 2x
\n" ); document.write( "6x - 3y = 12\r
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Algebra.Com's Answer #89522 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
#1\r
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\n" ); document.write( "\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"y=2x%2B6\"
\n" ); document.write( "\"y=-x-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-x-3%29=2x%2B6\" Plug in \"y=-x-3\" into the first equation. In other words, replace each \"y\" with \"-x-3\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-x-3%29=2x%2B6\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"-x-3=2x%2B6\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"-x=2x%2B6%2B3\"Add 3 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-x-2x=6%2B3\" Subtract 2x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=6%2B3\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=9\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%289%29%2F%28-3%29\" Divide both sides by -3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"x=-3\", we can plug this into \"y=-x-3\" to find \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-%28-3%29-3\" Substitute \"-3\" for each \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=0\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=-3\" and \"y=0\" which also looks like \r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the two equations, we can see that their intersection is at . So this verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+2x%2B6%2C+-x-3%29+\" Graph of \"y=2x%2B6\" (red) and \"y=-x-3\" (green)\r
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"-3%2Ax%2B1%2Ay=9\"
\n" ); document.write( " \"1%2Ax%2B2%2Ay=4\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"1%2Ay=9%2B3%2Ax\"Add \"3%2Ax\" to both sides
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\n" ); document.write( " \"y=%289%2B3%2Ax%29\" Divide both sides by 1.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=9%2B3%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"9%2B3%2Ax\" we can substitute the expression \"9%2B3%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"1%2Ax%2B2%2Ahighlight%28%289%2B3%2Ax%29%29=4\" Replace y with \"9%2B3%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"1%2Ax%2B2%2A%289%29%2B2%283%29x=4\" Distribute 2 to \"9%2B3%2Ax\"
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\n" ); document.write( " \"1%2Ax%2B18%2B6%2Ax=4\" Multiply
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\n" ); document.write( " \"1%2Ax%2B18%2B6%2Ax=4\" Reduce any fractions
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\n" ); document.write( " \"1%2Ax%2B6%2Ax=4-18\" Subtract \"18\" from both sides
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\n" ); document.write( " \"1%2Ax%2B6%2Ax=-14\" Combine the terms on the right side
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\n" ); document.write( " \"7%2Ax=-14\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F7%29%287%2F1%29%29x=%28-14%2F1%29%281%2F7%29\" Multiply both sides by \"1%2F7\". This will cancel out \"7%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"-14%2F1\" and \"1%2F7\" (and simplify) we get
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\n" ); document.write( " \"x=-2\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=-2\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"1%28-2%29%2B2%2Ay=4\" Plug in \"x=-2\" into the 2nd equation
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\n" ); document.write( " \"-2%2B2%2Ay=4\" Multiply
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\n" ); document.write( " \"2%2Ay=4%2B2\"Add \"2\" to both sides
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\n" ); document.write( " \"2%2Ay=6\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F2%29%282%29%29%2Ay=%286%2F1%29%281%2F2%29\" Multiply both sides by \"1%2F2\". This will cancel out 2 on the left side.
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\n" ); document.write( " \"y=6%2F2\" Multiply the terms on the right side
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\n" ); document.write( " \"y=3\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=3\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=-2\" and \"y=3\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"-2\",\"3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"-3%2Ax%2B1%2Ay=9\"
\n" ); document.write( " \"1%2Ax%2B2%2Ay=4\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"-3%2Ax%2B1%2Ay=9\" (red) and \"1%2Ax%2B2%2Ay=4\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"-2\",\"3\"). This verifies our answer.
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\n" ); document.write( " Plug in (\"-2\",\"3\") into the system of equations
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\n" ); document.write( " Let \"x=-2\" and \"y=3\". Now plug those values into the equation \"-3%2Ax%2B1%2Ay=9\"
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\n" ); document.write( " \"-3%2A%28-2%29%2B1%2A%283%29=9\" Plug in \"x=-2\" and \"y=3\"
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\n" ); document.write( " \"6%2B3=9\" Multiply
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\n" ); document.write( " \"9=9\" Add
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\n" ); document.write( " \"9=9\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-2\",\"3\") satisfies \"-3%2Ax%2B1%2Ay=9\"
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\n" ); document.write( " Let \"x=-2\" and \"y=3\". Now plug those values into the equation \"1%2Ax%2B2%2Ay=4\"
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\n" ); document.write( " \"1%2A%28-2%29%2B2%2A%283%29=4\" Plug in \"x=-2\" and \"y=3\"
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\n" ); document.write( " \"-2%2B6=4\" Multiply
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\n" ); document.write( " \"4=4\" Add
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\n" ); document.write( " \"4=4\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-2\",\"3\") satisfies \"1%2Ax%2B2%2Ay=4\"
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\n" ); document.write( " Since the solution (\"-2\",\"3\") satisfies the system of equations
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\n" ); document.write( " \"-3%2Ax%2B1%2Ay=9\"
\n" ); document.write( " \"1%2Ax%2B2%2Ay=4\"
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\n" ); document.write( " this verifies our answer.
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\n" ); document.write( "\n" ); document.write( "\"y+%2B+4+=+2x\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=+2x-4\" Solve for y by subtracting 4 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"6x-3y=12\"
\n" ); document.write( "\"y=2x-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x-3%282x-4%29=12\" Plug in \"y=2x-4\" into the first equation. In other words, replace each \"y\" with \"2x-4\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"6x-6x%2B12=12\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"12=12\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"0=12-12\"Subtract 12 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0=0\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"0=0\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "Since this equation is always true for any x value, this means x can equal any number. So there are an infinite number of solutions.
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