document.write( "Question 121952This question is from textbook Glencoe Mathematics Geometry
\n" ); document.write( ": Find the value of x so that the line containing points at (x,2) and (-4, 5) is perpendicular to the line containing points at (4,8) and (2,-1).\r
\n" ); document.write( "\n" ); document.write( "I have determined that the slope for the line containing (4,8) and 2,-1 is 9/2 and thus the slope for the perpendicular line would be -2/9. I figured that if I used the y2-y1 over x2-x1 and set that = to -2/9 that I would get the answer and it just is not working. The book says that the answer is 9.5. Can you help? \n" ); document.write( "
Algebra.Com's Answer #89517 by stanbon(75887)\"\" \"About 
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Find the value of x so that the line containing points at (x,2) and (-4, 5) is perpendicular to the line containing points at (4,8) and (2,-1).
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\n" ); document.write( "Yes the slope is -2/9
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\n" ); document.write( "EQUATION to solve for \"x\":
\n" ); document.write( "(2-5)/(x--4) = -2/9
\n" ); document.write( "Cross-multiply:
\n" ); document.write( "-2(x+4) = -27
\n" ); document.write( "x+4 = 13.5
\n" ); document.write( "x = 9.5 or 19/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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