document.write( "Question 121866This question is from textbook Algebra: structure and method: Book 1
\n" ); document.write( ": The sum of two numbers is 40. If twice the larger number is divided by the smaller, the quotient is 3 and the reminder is 10. Find the number. I NEED HELP. PLEASE!!!! The answer is 26 or 14, but I do not know how to get there. \n" ); document.write( "
Algebra.Com's Answer #89486 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
We will go thru this step-by-step
\n" ); document.write( "Let x = the larger number
\n" ); document.write( "Let y = the smaller number
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement
\n" ); document.write( "\"The sum of two numbers is 40.\"
\n" ); document.write( " x + y = 40
\n" ); document.write( "or we can say:
\n" ); document.write( " x = (40-y); use for substitution
\n" ); document.write( ":
\n" ); document.write( "\" If twice the larger number is divided by the smaller, the quotient is 3 and the reminder is 10.\"
\n" ); document.write( ":
\n" ); document.write( "If we think about long division, we can say that if we subtract 10 from 2x and
\n" ); document.write( "divide by y, the quotient will be an even 3, write the equation like that;\r
\n" ); document.write( "\n" ); document.write( " \"%282x-10%29%2Fy\" = 3
\n" ); document.write( "multiply both sides by y
\n" ); document.write( "2x - 10 = 3y
\n" ); document.write( "2x = 3y + 10
\n" ); document.write( ":
\n" ); document.write( "Find the number.
\n" ); document.write( ":
\n" ); document.write( "Substitute (40-y) for x in the above equation and find y
\n" ); document.write( "2(40-y) = 3y + 10
\n" ); document.write( "80 - 2y = 3y + 10
\n" ); document.write( "80 - 10 = 3y + 2y
\n" ); document.write( "70 = 5y
\n" ); document.write( "y = \"70%2F5\"
\n" ); document.write( "y = 14 is the smaller number
\n" ); document.write( ":
\n" ); document.write( "The larger number (x)
\n" ); document.write( "40 - 14 = 26 is the larger number
\n" ); document.write( "
\n" );