document.write( "Question 121862: Felicia and Rachelle are students in Mr. Johnston's Math 12 class. They got behind on their workcand need to finish seven assignments on the weekend. It would take Felicia 4 hours to finish the work by herself. It would take Rachelle 5 hours. If they worked together, how long would it take them to finish the work?
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Algebra.Com's Answer #89477 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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t would take Felicia 4 hours to finish the work by herself. It would take Rachelle 5 hours. If they worked together, how long would it take them to finish the work?
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\n" ); document.write( "Let t = time required if they work together:
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\n" ); document.write( "Let the completed work = 1
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\n" ); document.write( " $\"t%2F4\"$ + $\"t%2F5\"$ = 1
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\n" ); document.write( "Multiply equation by 20 to get rid of the denominator
\n" ); document.write( "20* $\"t%2F4\"$ + 20* $\"t%2F5\"$ = 20(1)
\n" ); document.write( "Cancel out the denominators and you have:
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\n" ); document.write( "5t + 4t = 20
\n" ); document.write( "9t = 20
\n" ); document.write( "t = $\"20%2F9\"$
\n" ); document.write( "t = 2.222 hr
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\n" ); document.write( "Change .222 hrs to minutes: .222 * 60 = 13.3 minutes
\n" ); document.write( "2 hrs 13 min working together:
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\n" ); document.write( "Check solution using the decimals
\n" ); document.write( "2.222/4 + 2.222/5 =
\n" ); document.write( ".5555 + .4444 = .9999 ~ 1
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