document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121879>Question 121879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the quadratic formula to solve\r<BR>\n" );
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document.write( "2x squared - 5x = 3\r<BR>\n" );
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document.write( "3x squared - 2x + 1 = 0\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89476 by </B><A HREF=/tutors/aboutme.mpl?userid=MathmaticsMaster><B>MathmaticsMaster(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathmaticsMaster><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2 - 5x = 3  Original problem.\r<BR>\n" );
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document.write( "2x^2 - 5x - 3 = 0 Bring eveything to one side and remember that when you bring something over to another side, the sign changes.\r<BR>\n" );
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document.write( "(2x - 1)(x + 3) = 0  Factor completely.\r<BR>\n" );
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document.write( "2x - 1 = 0    x + 3 = 0   Finish solving.\r<BR>\n" );
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document.write( "2x = 1   x = -3 Finish solving.\r<BR>\n" );
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document.write( "x = 1/2   x = -3 <<<<< answers\r<BR>\n" );
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