document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121873>Question 121873</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh>Algebra Structure and Method </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I have been working on this problem for 1 hour now and I am having troubles with it.  I was wondering if someone could help me with it.  Please and Thank You!!\r<BR>\n" );
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document.write( "Solve by whatever method you prefer, using one or two variables.\r<BR>\n" );
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document.write( "A chemist has 800g of a dye solution that is 20% of it original strength.  How much dye must be added to increase the strength to 50%?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89472 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .2*800+X=.5(800+X)<BR>\n" );
document.write( "160+X=400+.5X<BR>\n" );
document.write( "X-.5X=400-160<BR>\n" );
document.write( ".5X=240<BR>\n" );
document.write( "X=240/.5<BR>\n" );
document.write( "X=480g OF DYE NEEDS TO BE ADDED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".2*800+480=.5(800+480)<BR>\n" );
document.write( "160+480=.5(1280)<BR>\n" );
document.write( "640=640<BR>\n" );
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