document.write( "Question 121785:
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document.write( "jim has a total of 50 coins. Some are nickels and some are dimes. Altogether he has $4.15. How many dimes does he have? How many nickles? \n" );
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Algebra.Com's Answer #89449 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! N+D=50 OR N=50-D \n" ); document.write( ".05N+.10D=4.15 \n" ); document.write( "NOW REPLACE N WITH(50-D) & SOLVE FOR D \n" ); document.write( ".05(50-D)+.10D=4.15 \n" ); document.write( "2.50-.05D+.10D=4.15 \n" ); document.write( ".05D=4.15-2.50 \n" ); document.write( ".05D=1.65 \n" ); document.write( "D=1.65/.05 \n" ); document.write( "D=33 IS THE NUMBER OF DIMES. \n" ); document.write( "50-33=17 IS THE NUMBER OF NICKLES. \n" ); document.write( "PROOF \n" ); document.write( ".10*33+.05*17=4.15 \n" ); document.write( "3.30+85=4.15 \n" ); document.write( "4.15=4.15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |