document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121819>Question 121819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> May I have some help with the following equation?\r<BR>\n" );
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document.write( "(x+1/x)^2 + 4(x+1/x)+ 3=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89441 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89441\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let z=x+1/x then z^2+4z+3=0 then z=-1 or -3 then\r<BR>\n" );
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document.write( "x+1/x =-1 or x+1/x=-3  \r<BR>\n" );
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document.write( "if x+1/x = -1 then x^2+1=-x then x^2+x+1=0 ( no real solution)<BR>\n" );
document.write( "if x+1/x = -3 then x^2+1=-3x then x^2+3x+1=0 then\r<BR>\n" );
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document.write( "x=(-3+sqrt(5))/2 or\r<BR>\n" );
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document.write( "x=(-3-sqrt(5))/2 </SPAN>\n" );
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