document.write( "Question 121806: How would solve this system by addition?
\n" );
document.write( "2x - 4y = 7
\n" );
document.write( "4x - 2y = 9 \n" );
document.write( "
Algebra.Com's Answer #89425 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You really don't want to solve this system by 'addition.' What you want is to solve it by elimination, using addition as one of the steps of the process.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The idea of solving by elimination is to multiply (if necessary) one of the equations by some constant so that one of the variables will have a coefficient that is the additive inverse of the coefficient on the same variable in the other equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this example, multiply the first equation by -2, resulting in a coefficient on the x term of -4. -4 is the additive inverse of the 4 coefficient on x in the second equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you can add the two equations, term-by-term. That is, you add the x terms to the x terms, the y terms to the y terms, and the constants to the constants, resulting in one equation with a zero coefficient on one of the variables, in this case, x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by 6:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now that you have a value for y, you can either substitute that value into either one of the original equations and solve for x, or you could take the original two equations, multiply one of them by an appropriate constant to eliminate the y variable so that you can solve for x. Either way works. Watch carefully:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2nd equation times -2:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Achieving the same result.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore your solution set is the ordered pair ( \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check your answer:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First, algebraically:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second, graphically:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that the lines intersect at a point a little less than 2 [ |