document.write( "Question 121813: Angus invested $18000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #89422 by checkley71(8403) ![]() You can put this solution on YOUR website! .05X+.03(18000-X)=660 \n" ); document.write( ".05X+540-.03X=660 \n" ); document.write( ".05X-.03X=660-540 \n" ); document.write( ".02X=120 \n" ); document.write( "X=120/.02 \n" ); document.write( "X=6000 AMOUNT INVESTED @ 5%. \n" ); document.write( "18000-6000=12000 INVESTED @ 3%. \n" ); document.write( "PROOF \n" ); document.write( ".05*6000+.03*12000=660 \n" ); document.write( "300+360=660 \n" ); document.write( "660=660 \n" ); document.write( " |