document.write( "Question 121813: Angus invested $18000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #89422 by checkley71(8403)\"\" \"About 
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.05X+.03(18000-X)=660
\n" ); document.write( ".05X+540-.03X=660
\n" ); document.write( ".05X-.03X=660-540
\n" ); document.write( ".02X=120
\n" ); document.write( "X=120/.02
\n" ); document.write( "X=6000 AMOUNT INVESTED @ 5%.
\n" ); document.write( "18000-6000=12000 INVESTED @ 3%.
\n" ); document.write( "PROOF
\n" ); document.write( ".05*6000+.03*12000=660
\n" ); document.write( "300+360=660
\n" ); document.write( "660=660
\n" ); document.write( "
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