document.write( "Question 121755: The equation h=-16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground . Find the time it takes for the arrow to reach a height of 180 ft?\r
\n" ); document.write( "\n" ); document.write( "t = 180/112
\n" ); document.write( "t = 1.6 seconds\r
\n" ); document.write( "\n" ); document.write( "Not sure if I'm doing the problem right but just double checking.
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Algebra.Com's Answer #89402 by algebrapro18(249)\"\" \"About 
You can put this solution on YOUR website!
Well that was a nice try but wrong. What you need to do is solve the equation:
\n" ); document.write( "180 = -16t^2+112t for t and see what you get. \r
\n" ); document.write( "\n" ); document.write( "so solving we get:\r
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\n" ); document.write( "\n" ); document.write( "180 = -16t^2+112t --> Subtract 180 from both sides
\n" ); document.write( "0 = -16t^2+112t-180 --> factor out a 4 from the right hand side
\n" ); document.write( "0 = 4(-4t^2+18t-45) --> divide both sides by 4
\n" ); document.write( "0 = -4t^2+18t-45 --> factor
\n" ); document.write( "0 = (-2t+5)(2t-9) --> set each factor equal to zero and solve\r
\n" ); document.write( "\n" ); document.write( "-2t + 5 = 0 --> subtract 5 from both sides
\n" ); document.write( "-2t = -5 --> divide both sides by -2
\n" ); document.write( "t = 5/2 or 2.5\r
\n" ); document.write( "\n" ); document.write( "2t - 9 = 0 --> Add 9 to both sides
\n" ); document.write( "2t = 9 --> Divide both sides by 2
\n" ); document.write( "t = 9/2 or 4.5\r
\n" ); document.write( "\n" ); document.write( "so the arrow will reach a hight of 180 feet at 2.5 seconds and 4.5 seconds.
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