document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18607>Question 18607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> True or False.\r<BR>\n" );
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document.write( "The sum of the lengths of the diagonals of a rhombus is less than its perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8939 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cosider rhombus ABCD..we have AB=BC=CD=DA=x say..diagonals are AC and BD.consider triangle ABC..as per the property of triangles sum of any 2 sides is more than the third side..so<BR>\n" );
document.write( "AB+BC>AC..or  2x>AC<BR>\n" );
document.write( "similarly in triangle BCD,we have BC+CD>BD...or..2x>BD<BR>\n" );
document.write( "adding these 2 eqns...we have 2x+2x>AC+BD..or..4x>AC+BD<BR>\n" );
document.write( "so perimeter is more than sum of diagonals..or sum of diagonals is less than perimeter....TRUE </SPAN>\n" );
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