document.write( "Question 121704: Bacteria has a tripling time of 8 minutes. If there were initially 24 spores of bacteria on a hamburger, how many spores will be present after one hour ? \n" ); document.write( "
Algebra.Com's Answer #89380 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! At time = 0 there are 24 spores. \n" ); document.write( ". \n" ); document.write( "8 minutes later the number of spores has tripled. So after 8 minutes the number of spores is 24*3. \n" ); document.write( ". \n" ); document.write( "8 minutes after that [16 minutes total] the number of spores again triples. You started this \n" ); document.write( "8 minute block with 24*3 spores and you triple that to get [24*3]*3 = 24*3^2 \n" ); document.write( ". \n" ); document.write( "8 minutes after that [24 minutes total] the number of spores again triples. You started this \n" ); document.write( "8 minute block with 24*3^2 spores and you triple that to get [24*3^2]*3 = 24*3^3 \n" ); document.write( ". \n" ); document.write( "8 minutes after that [32 minutes total] the number of spores again triples. You started this \n" ); document.write( "8 minute block with 24*3^3 spores and you triple that to get [24*3^3]*3 = 24*3^4 \n" ); document.write( ". \n" ); document.write( "By now you may see that the pattern for this problem is 24*3^N where N is the number of the \n" ); document.write( "8 minute periods you have gone through. Since you are to go through 60 minutes, if you divide \n" ); document.write( "60 by 8 you find that you are going to go through 7.5 periods of 8 minutes each. So for this \n" ); document.write( "problem the pattern will result in: \n" ); document.write( ". \n" ); document.write( "Number of spores after 60 minutes = 24*(3^7.5) \n" ); document.write( ". \n" ); document.write( "You can calculate 3^7.5 several ways. One is to use a calculator that has an x^y key and replace \n" ); document.write( "x with 3 and y with 7.5 to find the answer of 3787.995116. Another way is to recognize that 3^7.5 \n" ); document.write( "is equal to (3^3)*(3^3)*(3^1)*(3^0.5). But 3^3 = 3*3*3 = 27 and 3^1 = 3 you can substitute \n" ); document.write( "27 for 3^3 and 3 for 3^1 to get: \n" ); document.write( ". \n" ); document.write( "(3^3)*(3^3)*(3^1)*(3^0.5)= (27)*(27)*(3)*(3^0.5) = 2187*(3^0.5) \n" ); document.write( ". \n" ); document.write( "But 3^0.5 is 3^(1/2) and this is another way of writing the square root of 3. So 3^7.5 is \n" ); document.write( "equivalent to 2187 times the square root of 3. And if you calculate this you again get that \n" ); document.write( "3^7.5 = 3787.995116 \n" ); document.write( ". \n" ); document.write( "Now all you have to do to get the number of spores after 60 minutes is to return to the equation: \n" ); document.write( ". \n" ); document.write( "Number of spores after 60 minutes = 24*(3^7.5) \n" ); document.write( ". \n" ); document.write( "and substitute 3787.995116 for 3^7.5 and the equation becomes: \n" ); document.write( ". \n" ); document.write( "Number of spores after 60 minutes = 24*(3^7.5) = 24*3787.995116 = 90911.88279 \n" ); document.write( ". \n" ); document.write( "And this rounds to 90912 spores. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem a little better and to see how you can think \n" ); document.write( "your way through to the answer (with a little calculator help). \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |