document.write( "Question 121727: Can you please help me with this problem?\r
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document.write( "y1= 1/x+2, y2= 1/x-2, y3= 1/x^2-4, and the difference between 4 times y1 and 7 times y2 is the product of 11 and y3. Show equation and solve \n" );
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Algebra.Com's Answer #89359 by stanbon(75887) ![]() You can put this solution on YOUR website! Can you please help me with this problem?\r \n" ); document.write( "\n" ); document.write( "y1= 1/x+2 \n" ); document.write( "y2= 1/x-2 \n" ); document.write( "y3= 1/x^2-4 \n" ); document.write( "the difference between 4 times y1 and 7 times y2 is the product of 11 and y3. Show equation and solve \n" ); document.write( "--------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "4y1-7y2=11y3 \n" ); document.write( "Substitute to get: \n" ); document.write( "[4/(x+2) - 7/(x-2)] = 11/(y^2-4) \n" ); document.write( "------------------ \n" ); document.write( "Multiply thru by y^2-4 to get \n" ); document.write( "4(y-2) - 7(y+2) = 11 \n" ); document.write( "-3y-10 = 11 \n" ); document.write( "-3y = 21 \n" ); document.write( "y = -7 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |