document.write( "Question 121727: Can you please help me with this problem?\r
\n" ); document.write( "\n" ); document.write( "y1= 1/x+2, y2= 1/x-2, y3= 1/x^2-4, and the difference between 4 times y1 and 7 times y2 is the product of 11 and y3. Show equation and solve
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Algebra.Com's Answer #89359 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Can you please help me with this problem?\r
\n" ); document.write( "\n" ); document.write( "y1= 1/x+2
\n" ); document.write( "y2= 1/x-2
\n" ); document.write( "y3= 1/x^2-4
\n" ); document.write( "the difference between 4 times y1 and 7 times y2 is the product of 11 and y3. Show equation and solve
\n" ); document.write( "---------------------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "4y1-7y2=11y3
\n" ); document.write( "Substitute to get:
\n" ); document.write( "[4/(x+2) - 7/(x-2)] = 11/(y^2-4)
\n" ); document.write( "------------------
\n" ); document.write( "Multiply thru by y^2-4 to get
\n" ); document.write( "4(y-2) - 7(y+2) = 11
\n" ); document.write( "-3y-10 = 11
\n" ); document.write( "-3y = 21
\n" ); document.write( "y = -7
\n" ); document.write( "========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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