document.write( "Question 121717: A boy has planned a three-hour bicycle ride. After biking at a rate of 14 mph for awhile, the bike breaks down and he rides back with his father at a rate of thirty-five mph. How far did the boy ride his bicycle if he returns one hour after he left? \n" ); document.write( "
Algebra.Com's Answer #89358 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A boy has planned a three-hour bicycle ride. After biking at a rate of 14 mph for awhile, the bike breaks down and he rides back with his father at a rate of thirty-five mph. How far did the boy ride his bicycle if he returns one hour after he left? \n" ); document.write( ": \n" ); document.write( "Let d = distance ridden on the bike \n" ); document.write( ": \n" ); document.write( "Write two time equations with the information we have: Time = Distance/speed \n" ); document.write( ": \n" ); document.write( "time on the bike = \n" ); document.write( ": \n" ); document.write( "Time in the car = \n" ); document.write( ": \n" ); document.write( "Time on bike + time in car = 1 hr \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 14*35 = 490, to get rid of the denominators \n" ); document.write( "490* \n" ); document.write( "Cancel the denominators and you have: \n" ); document.write( ": \n" ); document.write( "35d + 14d = 490 \n" ); document.write( ": \n" ); document.write( "49d = 490 \n" ); document.write( "d = \n" ); document.write( "d = 10 miles \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the total time \n" ); document.write( "10/14 + 10/35 = \n" ); document.write( ".714 + .286 = 1 hr, confirms our solution \n" ); document.write( ": \n" ); document.write( "Did this make sense to you? Any questions? \n" ); document.write( " \n" ); document.write( " |