document.write( "Question 121726: Please help me answer this question:\r
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document.write( "I started this:\r
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document.write( "(1/8)-2/3 = 1/(1/8)-2/3) = 1 x (8/1)-2/3 this is where I get stuck.\r
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document.write( "Thanks. \n" );
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Algebra.Com's Answer #89357 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Your problem is either subtracting fractions or taking fractions to a fractional power. \n" ); document.write( "We can look at both. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Subtractng fractions. \n" ); document.write( "Whenever you add or subtract fractions you need to have the same denominator. \n" ); document.write( "The easiest way to get a common denominator is to make it the product of your two denominators. \n" ); document.write( " \n" ); document.write( "Now find each fraction as an equivalent fraction with denominator of 24. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now you can subtract. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Taking fractions to a fractional power. \n" ); document.write( " \n" ); document.write( "You can also look at 1/8 as \n" ); document.write( " \n" ); document.write( "From your exponentiation rules, \n" ); document.write( " \n" ); document.write( "Then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |