document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121696>Question 121696</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0132337223/algebrahomeworkh>Elementary and Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Find solution to each system of equations by substitution <BR>\n" );
document.write( " I am still struggling  using substitution method given 2 equations. Any help (detailed instructions) you can give me so i understand would be very much appreciated. <BR>\n" );
document.write( "  This is what I have gotten so far and its not working.  <BR>\n" );
document.write( "Problem:       6X+3Y=30 and 2X+3Y=18 <BR>\n" );
document.write( "2(30-3Y) over 6 = 3Y =18 <BR>\n" );
document.write( "60 + Y over 6 + 3Y =18 <BR>\n" );
document.write( "10/6 y =3y =18 <BR>\n" );
document.write( "5/3=3y =18 <BR>\n" );
document.write( "-3y=-5/3 +18<BR>\n" );
document.write( "y = 5/3 +18  <BR>\n" );
document.write( "  Then I lose it. Know its not right but don't know how to correct it. <BR>\n" );
document.write( "It throws me when given a Y on one side and a X on the other side of the equation. How do i separate them? Then they throw a statement of multiply the equation by a number. Which number do I use?  Then I run into another problem same as above only it has a -Y and a +Y number.  \r<BR>\n" );
document.write( "\n" );
document.write( "Problem: 1/2x + 2y = 5, 3X-1/2y =5  now I am dealing with fractions?           Please help me. <BR>\n" );
document.write( "Thank You.    </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89344 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The simple rule is: whatever you do to<BR>\n" );
document.write( "one side of an equation, you have to do<BR>\n" );
document.write( "to the other side<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x+%2B+3y+=+30 ALIGN=MIDDLE  ALT=\"6x+%2B+3y+=+30\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+%2B+3y+=+18 ALIGN=MIDDLE  ALT=\"2x+%2B+3y+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "What I see right away is I can divide both sides of the<BR>\n" );
document.write( "1st equation by 3 without getting any fractions<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+%2B+y+=+10 ALIGN=MIDDLE  ALT=\"2x+%2B+y+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now, to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" > alone on the left side, <BR>\n" );
document.write( "I subtract <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x ALIGN=MIDDLE  ALT=\"2x\"   DISABLED_style= \"max-width:90%; height:auto;\" > from both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+10+-+2x ALIGN=MIDDLE  ALT=\"y+=+10+-+2x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now I can substitute this <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "in the 2nd equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+%2B+3%2810+-+2x%29+=+18 ALIGN=MIDDLE  ALT=\"2x+%2B+3%2810+-+2x%29+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+%2B+30+-+6x+=+18 ALIGN=MIDDLE  ALT=\"2x+%2B+30+-+6x+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30+-+4x+=+18 ALIGN=MIDDLE  ALT=\"30+-+4x+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now add <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x ALIGN=MIDDLE  ALT=\"4x\"   DISABLED_style= \"max-width:90%; height:auto;\" > to both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30+=+4x+%2B+18 ALIGN=MIDDLE  ALT=\"30+=+4x+%2B+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now subtract <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=18 ALIGN=MIDDLE  ALT=\"18\"   DISABLED_style= \"max-width:90%; height:auto;\" > from both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30+-+18+=+4x ALIGN=MIDDLE  ALT=\"30+-+18+=+4x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12+=+4x ALIGN=MIDDLE  ALT=\"12+=+4x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "divide both sides by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4 ALIGN=MIDDLE  ALT=\"4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+3 ALIGN=MIDDLE  ALT=\"x+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > answer<BR>\n" );
document.write( "Now you can use either equation to find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+%2B+3y+=+18 ALIGN=MIDDLE  ALT=\"2x+%2B+3y+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A3+%2B+3y+=+18 ALIGN=MIDDLE  ALT=\"2%2A3+%2B+3y+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6+%2B+3y+=+18 ALIGN=MIDDLE  ALT=\"6+%2B+3y+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "subtract <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6 ALIGN=MIDDLE  ALT=\"6\"   DISABLED_style= \"max-width:90%; height:auto;\" > from both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y+=+12 ALIGN=MIDDLE  ALT=\"3y+=+12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+4 ALIGN=MIDDLE  ALT=\"y+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" > answer<BR>\n" );
document.write( "You can check these answers by substituting<BR>\n" );
document.write( "back into original equations   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );