document.write( "Question 121698: A mother is four times as old as her daughter. In 20 years she will be twice as old as her daughter. How old are mother and daughter now? \n" ); document.write( "
Algebra.Com's Answer #89343 by josmiceli(19441)\"\" \"About 
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Let \"m\" = Mother's age now
\n" ); document.write( "Let \"d\" = daughter's age now
\n" ); document.write( "\"m+=+4d\"
\n" ); document.write( "Read the 2nd part as: When both Mother and Daughter are
\n" ); document.write( "20 years older, The mother will be twice as old
\n" ); document.write( "\"m+%2B+20+=+2%28d+%2B+20%29\"
\n" ); document.write( "Substitute 1st equation into 2nd
\n" ); document.write( "\"4d+%2B+20+=+2d+%2B+40\"
\n" ); document.write( "\"2d+=+20\"
\n" ); document.write( "\"d+=+10\" daughter's age now
\n" ); document.write( "\"m+=+4d\"
\n" ); document.write( "\"m+=+40\" mother's age now
\n" ); document.write( "check:
\n" ); document.write( "\"m+%2B+20+=+2%28d+%2B+20%29\"
\n" ); document.write( "\"40+%2B+20+=+2%2810+%2B+20%29\"
\n" ); document.write( "\"60+=+2%2A30\"
\n" ); document.write( "\"60+=+60\"
\n" ); document.write( "OK
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