document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121663>Question 121663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x/3=x/2+6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89339 by </B><A HREF=/tutors/aboutme.mpl?userid=jainenderkapoor><B>jainenderkapoor(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jainenderkapoor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jainenderkapoor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x/3 = x/2 + 6<BR>\n" );
document.write( "Multiplying throughout by 6  which is LCM of 3 and 2\r<BR>\n" );
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document.write( "4x = 3x + 36<BR>\n" );
document.write( "4x - 3x = 36<BR>\n" );
document.write( "x = 36\r<BR>\n" );
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document.write( "Hope the solution is clear to you. If you have any doubt you can contact me at jainenderkapoor@gmail.com   I am also available for Online Tutoring at very reasonable rates. </SPAN>\n" );
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