document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121672>Question 121672</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of forty-five mph. At what rate must she return if the total travel time is three hours and forty minutes? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89321 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 90/45=2 HOURS FOR THE GOING TRIP.<BR>\n" );
document.write( "90/X=(3 2/3-2)<BR>\n" );
document.write( "90/X=(1 1/3)<BR>\n" );
document.write( "(1 1/3)X=90<BR>\n" );
document.write( "X=90/(1 1/3)<BR>\n" );
document.write( "X=67.5 MPH FOR THE RETURN TRIP.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*45+(1 1/3)*67.5=180<BR>\n" );
document.write( "90+90=180<BR>\n" );
document.write( "180=180<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );