document.write( "Question 121661: what is the y-intercept of the line that is parallel to the line 2x+3y=4 and contains the point (3,-1) \n" ); document.write( "

Algebra.Com's Answer #89316 by checkley71(8403) $\"\"$ $\"About$

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2X+3Y=4
\n" ); document.write( "3Y=-2X+4
\n" ); document.write( "Y=-2X/3+4/3 THIS LINE HAS A SLOPE=-2/3. (RED LINE)
\n" ); document.write( "THUS ANY PARALLEL LINE ALSO HAS A SLOPE=-2/3 & IF IT PASSES THROUGH(3,-1) THEN WE HAVE THE EQUATION:
\n" ); document.write( "-1=-2/3*3+b
\n" ); document.write( "-1=-2+b
\n" ); document.write( "b=-1+2
\n" ); document.write( "b=1 SO THE EQUATION IS:
\n" ); document.write( "Y=-2X/3+1 (GREEN LINE)
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-2x%2F3+%2B4%2F3%2C+y+=+-2x%2F3+%2B1%29+\"$ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions y = -2x/3 +4/3 and y = -2x/3 +1). \n" ); document.write( "

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