document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121640>Question 121640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangular picture is 34 cm and the diagonal is 13 cm. find the dimensions of the picture. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89309 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a and b the sides of the rectangular picture <BR>\n" );
document.write( "then 2(a+b)=34 then\r<BR>\n" );
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document.write( " a+b=17\r<BR>\n" );
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document.write( "and using the diagonal is 13 and pitagoras then \r<BR>\n" );
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document.write( "a^2+b^2=13^2\r<BR>\n" );
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document.write( "a^2+(17-a)^2=169<BR>\n" );
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document.write( "a^2+289-34a+a^2=169\r<BR>\n" );
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document.write( "2a^2-34a+120=0<BR>\n" );
document.write( "a^2-17a+60=0\r<BR>\n" );
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document.write( "the solution to this equation a=12  and a=5 then\r<BR>\n" );
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document.write( "the dimensions are 12 and 5 cms\r<BR>\n" );
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