document.write( "Question 121640: the perimeter of a rectangular picture is 34 cm and the diagonal is 13 cm. find the dimensions of the picture. \n" ); document.write( "
Algebra.Com's Answer #89304 by checkley71(8403)\"\" \"About 
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13^2=a^2+b^2 where 34/2=17 or a+b=17 or a=17-b
\n" ); document.write( "13^2=(17-b)^2+b^2
\n" ); document.write( "169=289-34b+b^2+b^2
\n" ); document.write( "2b^2-34b+289-169=0
\n" ); document.write( "2b^2-34b+120=0
\n" ); document.write( "2(b^2-17b+60)=0
\n" ); document.write( "2(b-12)(b-5)=0
\n" ); document.write( "b-12=0
\n" ); document.write( "b=12 one side
\n" ); document.write( "b-5=0
\n" ); document.write( "b=5 the other side.
\n" ); document.write( "proof
\n" ); document.write( "2*12+2*5=34
\n" ); document.write( "24+10=34
\n" ); document.write( "34=34
\n" ); document.write( "12^2+5^2=13^2
\n" ); document.write( "144+25=169
\n" ); document.write( "1169=169
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