document.write( "Question 121634: Using Substitution to Solve Linear Systems of Equations
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document.write( "1. y= x -1
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document.write( "2x -y =0\r
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document.write( "2. x+y= -3
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document.write( "3x+y= 3\r
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document.write( "3. x-y= 4
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document.write( "x-2y= 10\r
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document.write( "4.3x +y=0
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document.write( "x-y= 4\r
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document.write( "5. 2x +5y = 4
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document.write( "x +5y = 7\r
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document.write( "6.-3x + y = -3
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document.write( "2x- 5y = -11\r
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document.write( "7. 2x -3y = -14
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document.write( "3x-y= -7\r
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document.write( "8.x-5y= -3
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document.write( "4x -3y= 5\r
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document.write( "9.x-2y=0
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document.write( "2x - y =6 \n" );
document.write( "
Algebra.Com's Answer #89295 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! y=x-1 now replace y with (x-1) in the other equation. \n" ); document.write( "2x-(x-1)=0 \n" ); document.write( "2x-x+1=0 \n" ); document.write( "x+1=o \n" ); document.write( "x=-1 answer. \n" ); document.write( "y=-1-1 \n" ); document.write( "y=-2 answer. \n" ); document.write( "------------------------------------ \n" ); document.write( "x+y=-3 \n" ); document.write( "y=-x-3 now replace y with (-x-3) in the other equation & solve for x \n" ); document.write( "3x+(-x-3)=3 \n" ); document.write( "3x-x-3=3 \n" ); document.write( "2x=3=3 \n" ); document.write( "2x=6 \n" ); document.write( "x=6/2 \n" ); document.write( "x=3 answer. \n" ); document.write( "y=-3-3 \n" ); document.write( "y=-6 answer. \n" ); document.write( "---------------------------------------------- \n" ); document.write( "These is two procedures for the substitution method. \n" ); document.write( "We are not here to do your homework but to show you how to solve problems step by step which I have done. \n" ); document.write( " \n" ); document.write( " |