document.write( "Question 121605: The demand and supply equations for a certain item are given by
\n" ); document.write( " D = –5p + 40
\n" ); document.write( " S = –p2 + 30p – 8
\n" ); document.write( "Find the equilibrium price.\r
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Algebra.Com's Answer #89291 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
[y=-5x+40] (red line) & [y=-x^2+30x-8] (green line)
\n" ); document.write( "-5P+40=-P^2+30P-8
\n" ); document.write( "P^2-5P-30P+40+8=0
\n" ); document.write( "P^2-35P+48=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "P=(35+-SQRT[-35^2-4*1*48])/2*1
\n" ); document.write( "P=(35+-SQRT[1225-192])/2
\n" ); document.write( "P=(35+-SQRT1033])/2
\n" ); document.write( "P=(35+-32.14)/2
\n" ); document.write( "P=(35+32.14)/2
\n" ); document.write( "P=67.14/2
\n" ); document.write( "P=33.57 ANSWER.
\n" ); document.write( "P=(35-32.14)/2
\n" ); document.write( "P=2.86/2
\n" ); document.write( "P=1.43 ANSWER.
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\n" ); document.write( "A GRAPHIC SOLUTION IS:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C500%2C+-60%2C+50%2C+-50%2C+240%2C+y+=+-5x+%2B40+%2C+y+=+-x%5E2+%2B30x+-8%29+\" (graph 500x500 pixels, x from -60 to 50, y from -50 to 240, of TWO functions y = -5x +40 and y = -x^2 +30x -8). \r
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