document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121608>Question 121608</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle whose perimeter is 40 cm, the length of the longest side is four cm less than the sum of th lengths of the other sides. The length of the shortest side is four cm more than the difference between the lengths of the other sides. What is the length of the longest side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89284 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89284\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LONGEST SIDE (C)=(A+B-4)<BR>\n" );
document.write( "SHORTEST SIDE (A)=4+(A+B-4)-B<BR>\n" );
document.write( "THE THREE SIDES ARE:(C)(A+B-4), (A)[4+(A+B-4)-B & (B)<BR>\n" );
document.write( "40=A+B-4+4+A+B-4-B+B<BR>\n" );
document.write( "40=2A+2B-4<BR>\n" );
document.write( "2A+2B-4-40=0<BR>\n" );
document.write( "2A=2B-44=0<BR>\n" );
document.write( "2(A+B-22)=0<BR>\n" );
document.write( "A+B-22=0<BR>\n" );
document.write( "A+B=22<BR>\n" );
document.write( "C=(A+B)-4<BR>\n" );
document.write( "C=22-4<BR>\n" );
document.write( "C=18 CM IS THE LONGEST SIDE.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );