document.write( "Question 121615: how do i divide these two problems:\r
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document.write( "y^2-12y+20 /y-2\r
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document.write( "and 2x^2+7x+3 / 2x+1\r
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document.write( " i need the steps for these two problems by today january 21,2008 at 8:00pm\r
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document.write( "please its urgent \n" );
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Algebra.Com's Answer #89283 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! y^2-12y+20 /y-2 \n" ); document.write( "Factor to get: \n" ); document.write( "= [(y-2)(Y-10)]/(y-2 \n" ); document.write( "= y-10 \n" ); document.write( "=========================================\r \n" ); document.write( "\n" ); document.write( "2x^2+7x+3 / 2x+1 \n" ); document.write( "Factor to get: \n" ); document.write( "= [2x^2+6x+x+3]/(2x+1)\r \n" ); document.write( "\n" ); document.write( "= [2x(x+3)+(x+3)]/(2x+1\r \n" ); document.write( "\n" ); document.write( "= [(x+3)(2x+1)]/(2x+1) \n" ); document.write( "---------------- \n" ); document.write( "Comment: \n" ); document.write( "Are you sure that denominator is not 2x+1 ? \n" ); document.write( "------------------ \n" ); document.write( "Well, you say it is 2x+1 so you can cancel the 2x+1 in numerator and denominator to get: \n" ); document.write( "= x+3 \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |