document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121457>Question 121457</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x-y=6 and 3x(squared)+3xy-6y(squared)=60, then 9x+18y=? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89275 by </B><A HREF=/tutors/aboutme.mpl?userid=jaymore><B>jaymore(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jaymore><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3xsquared+3xy-6ysquared=60...Factorise <BR>\n" );
document.write( "3x(x+2y)-3y(x+2y)=60<BR>\n" );
document.write( "(3x-3y)(x+2y)=60....1\r<BR>\n" );
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document.write( " 3x-3y can be written as 3(x-y)...2\r<BR>\n" );
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document.write( "Substitute x-y=6 in 2 above <BR>\n" );
document.write( "Now 3x-3y=18\r<BR>\n" );
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document.write( "go back to 1 above and plug in 18<BR>\n" );
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document.write( "18(x+2y)=60....Divide both sides by 18<BR>\n" );
document.write( "x+2y=60/18........3\r<BR>\n" );
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document.write( "9x+18y can be written as 9(x+2y)\r<BR>\n" );
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document.write( " 9(x+2y)=9times60/18=30 </SPAN>\n" );
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