document.write( "Question 121450: The length of a rectangle is 1 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #89272 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
LENGTH=2W+1
\n" ); document.write( "WIDTH=2L+2W=32
\n" ); document.write( "2(2W+1)+2W=32
\n" ); document.write( "4W+2+2W=32
\n" ); document.write( "6W=32-2
\n" ); document.write( "6W=30
\n" ); document.write( "W=30/6
\n" ); document.write( "W=5 IS THE WIDTH.
\n" ); document.write( "L=2*5+1
\n" ); document.write( "L=10+1
\n" ); document.write( "L=11 IS THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*5+2*11=32
\n" ); document.write( "10+22=32
\n" ); document.write( "32=32
\n" ); document.write( "
\n" );