document.write( "Question 121526:
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document.write( "how many gallons of a 70% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method \n" );
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Algebra.Com's Answer #89257 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .7X+.25*100=.6(100+X) \n" ); document.write( ".7X+25=60+.6X \n" ); document.write( ".7X-.6X=60-25 \n" ); document.write( ".1X=35 \n" ); document.write( "X=35/.1 \n" ); document.write( "X=350 GALLONS OF 70% ANTIFREEZE WILL BE NEEDED. \n" ); document.write( "PROOF \n" ); document.write( ".7*350+25=.6*450 \n" ); document.write( "245+25=270 \n" ); document.write( "270=270 \n" ); document.write( " \n" ); document.write( " |