document.write( "Question 121526:
\n" ); document.write( "how many gallons of a 70% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method
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Algebra.Com's Answer #89257 by checkley71(8403)\"\" \"About 
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.7X+.25*100=.6(100+X)
\n" ); document.write( ".7X+25=60+.6X
\n" ); document.write( ".7X-.6X=60-25
\n" ); document.write( ".1X=35
\n" ); document.write( "X=35/.1
\n" ); document.write( "X=350 GALLONS OF 70% ANTIFREEZE WILL BE NEEDED.
\n" ); document.write( "PROOF
\n" ); document.write( ".7*350+25=.6*450
\n" ); document.write( "245+25=270
\n" ); document.write( "270=270
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