document.write( "Question 121494: Can you help me solve the following problem. It is to Factor the polynomial completely.\r
\n" ); document.write( "\n" ); document.write( "\"27p%5E3-1\"\r
\n" ); document.write( "\n" ); document.write( "I really appriciate it. I am not getting this section at all.
\n" ); document.write( "

Algebra.Com's Answer #89243 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"27p%5E3-1\" Start with the given expression.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%283p%29%5E3-%281%29%5E3\" Rewrite \"27p%5E3\" as \"%283p%29%5E3\". Rewrite \"1\" as \"%281%29%5E3\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%283p-1%29%28%283p%29%5E2%2B%283p%29%281%29%2B%281%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%283p-1%29%289p%5E2%2B3p%2B1%29\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"27p%5E3-1\" factors to \"%283p-1%29%289p%5E2%2B3p%2B1%29\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words, \"27p%5E3-1=%283p-1%29%289p%5E2%2B3p%2B1%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );