document.write( "Question 104837: In a collection of nickels and dimes the number of dimes is 3 more than twice the number of nickels. If the value of the collection is $1.80, how many coins are there? \n" ); document.write( "
Algebra.Com's Answer #89240 by solver91311(24713)\"\" \"About 
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n = number of nickels
\n" ); document.write( "d = number of dimes\r
\n" ); document.write( "\n" ); document.write( "value of one nickel is 5 cents, so the value of n nickels is 5n cents
\n" ); document.write( "value of one dime is 10 cents, so the value of d dimes is 10d cents\r
\n" ); document.write( "\n" ); document.write( "The number of dimes (d) is (=) 3 more (+3) than twice the number of nickels (2n), so\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+2n+%2B+3\" \r
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\n" ); document.write( "\n" ); document.write( "The value of the collection, that is the value of the dimes plus the value of the nickels is $1.80 or 180 cents, so\r
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\n" ); document.write( "\n" ); document.write( "\"5n+%2B+10d+=+180\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute the expression for d from the first equation into the second equation:\r
\n" ); document.write( "\n" ); document.write( "\"cartoon%285n+%2B+10%2Ared%28d%29+=+180%2C5n+%2B+10%2Ared%28%282n%2B3%29%29=180%29\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify and solve:\r
\n" ); document.write( "\n" ); document.write( "\"5n+%2B+10%282n%2B3%29=180\"
\n" ); document.write( "\"5n%2B20n%2B30=180\"
\n" ); document.write( "\"25n=150\"
\n" ); document.write( "\"n=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=2%286%29%2B3=15\"\r
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\n" ); document.write( "\n" ); document.write( "So there are \"d%2Bn=15%2B6=21\" coins.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"10%2A15=150\"
\n" ); document.write( "\"5%2A6=30\"
\n" ); document.write( "and \"150%2B30=180\"
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