document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121556>Question 121556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi. May I have some help with the following problem?\r<BR>\n" );
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document.write( "For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the following formula, where d is measured in feet. Kerry wants her stopping distance not to exceed d = 400 ft. At what range of speeds can she travel?\r<BR>\n" );
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document.write( "d=v+(v^2)/20  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89223 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 400=V+(V^2)/20<BR>\n" );
document.write( "400=(20V+V^2)/20 CROSS MULTIPLY<BR>\n" );
document.write( "V^2+20V=20*400<BR>\n" );
document.write( "V^2+20V=8000<BR>\n" );
document.write( "V^2+20V-8000=0<BR>\n" );
document.write( "(V+100)(V-80)=0<BR>\n" );
document.write( "V-80=0<BR>\n" );
document.write( "V=80 MPH OR LESS IS THE ANSWER. </SPAN>\n" );
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