document.write( "Question 121488: The ratio of the length to the width of a rectangle is 5:4. If the length is increased by 8 and the width halved, the ratio of the length to the width of the new rectangle is 7:2. Find the dimensions of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #89202 by jaymore(5)\"\" \"About 
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Let the denote length by L and Width by W\r
\n" ); document.write( "\n" ); document.write( "L:W=5:4.......(1)\r
\n" ); document.write( "\n" ); document.write( "New dimensions after length is increased by 8 and width halved
\n" ); document.write( "L+8:1/2W=7:2........equation (2)\r
\n" ); document.write( "\n" ); document.write( "Solve the two equations\r
\n" ); document.write( "\n" ); document.write( "L/W=5/4...multiply both sides by W \r
\n" ); document.write( "\n" ); document.write( "L=5/4W\r
\n" ); document.write( "\n" ); document.write( "L+8/1/2W=7/2....cross multiply\r
\n" ); document.write( "\n" ); document.write( "2(L+8)=7/2W...open parenthesis
\n" ); document.write( "2L+16=7/2W\r
\n" ); document.write( "\n" ); document.write( "Substitute 5/4W for L
\n" ); document.write( "2(5/4W)+16=7/2W
\n" ); document.write( "5/2W+16=7/2W...like terms together
\n" ); document.write( "7/2W-5/2W=16
\n" ); document.write( "2W/2=16..Divide by 2 on both sides
\n" ); document.write( "W=16
\n" ); document.write( "L=5/4W=5/4times16=20
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