document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121541>Question 121541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried to figure out how to properly graph this problem however, when I looked at the answer already provided and what I had come up with became confused because they did not seem to match. x-2y=8 and 3x-2y=12. Here is what I have worked out so far.<BR>\n" );
document.write( "x-2y = 8									<BR>\n" );
document.write( "-2y = -x + 8									<BR>\n" );
document.write( "y = x/2 - 4									<BR>\n" );
document.write( "y intercept: (0, -4)									<BR>\n" );
document.write( "slope: 1/2 									\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "3x-2y = 12										<BR>\n" );
document.write( "-2y = -3x + 12										<BR>\n" );
document.write( "y = 3x/2 - 6										<BR>\n" );
document.write( "y intercept: (0, -6)										<BR>\n" );
document.write( "slope: 3/2 										\r<BR>\n" );
document.write( "\n" );
document.write( "I assume I would graph with the following points (0,-4) and (4,0) for the second one I assumed I would graph the following points (0,-6) (6,0). I think I have confused the actual points in which I am to graph. Could you please tell me if I am graphing the correct points? I do not have the ISBN for this book becasue it is an online class. Thanks and have a great day!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89200 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope-intercept form is one way of doing it but I don't think it's as intuitive as finding the x and y intercepts. <BR>\n" );
document.write( "Let's do it a different way. <BR>\n" );
document.write( "Find the x-intercept of the graph.<BR>\n" );
document.write( "Then find the y-intercept of the graph. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-2y+=+8 ALIGN=MIDDLE  ALT=\"x-2y+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "When y=0, then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-2%280%29=8 ALIGN=MIDDLE  ALT=\"x-2%280%29=8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=8 ALIGN=MIDDLE  ALT=\"x=8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "When x=0, then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0-2y=8 ALIGN=MIDDLE  ALT=\"0-2y=8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-4 ALIGN=MIDDLE  ALT=\"y=-4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now you have two points on the graph (0,-4) and (8,0). <BR>\n" );
document.write( "It’s easier to graph this way than with a point and the slope, I think. <BR>\n" );
document.write( "First graph the two points. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2Cgrid%28+1+%29%2Ccircle%28+0%2C-4%2C+.3+%29%2Ccircle%288%2C0%2C.3%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Then draw the line containing the two points. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2Cgrid%28+1+%29%2Ccircle%28+0%2C-4%2C+.3+%29%2Ccircle%288%2C0%2C.3%29%2Cgreen%28line%28+-12%2C+-10%2C+20%2C+6%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x-2y=12 ALIGN=MIDDLE  ALT=\"3x-2y=12\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "When y=0, then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x-2%280%29=12 ALIGN=MIDDLE  ALT=\"3x-2%280%29=12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=4 ALIGN=MIDDLE  ALT=\"x=4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "When x=0, then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%280%29-2y=12 ALIGN=MIDDLE  ALT=\"3%280%29-2y=12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=6 ALIGN=MIDDLE  ALT=\"y=6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The two points on the graph are(4,0) and (0,6). <BR>\n" );
document.write( "Graph the two points. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2Cgrid%28+1+%29%2Ccircle%28+4%2C0%2C+.3+%29%2Ccircle%280%2C6%2C.3%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Then draw the line containing the two points. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2Cgrid%28+1+%29%2Ccircle%28+4%2C0%2C+.3+%29%2Ccircle%280%2C6%2C.3%29%2Cgreen%28line%28+-12%2C+24%2C+12%2C+-12%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You can then look at your graphs and find the slope by using change in y divided by change in x. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5B1%5D=1%2F2 ALIGN=MIDDLE  ALT=\"m%5B1%5D=1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5B2%5D=-3%2F2 ALIGN=MIDDLE  ALT=\"m%5B2%5D=-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );