document.write( "Question 121474: write an equation of the line that is perpendicular to the line through(9, 10) and (3,-2) and passes through the x intercept of that line? \n" ); document.write( "

Algebra.Com's Answer #89150 by checkley71(8403) $\"\"$ $\"About$

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find the slope (-2-10)/(3-9)=-12/6=-2 this is the slope
\n" ); document.write( "Y=mX+b
\n" ); document.write( "10=-2*9+b
\n" ); document.write( "b=10+18
\n" ); document.write( "b=28 THUS THE EQUATION OF THIS LINE IS:
\n" ); document.write( "Y=-2X+28 (RED LINE)
\n" ); document.write( "THIS LINE HAS AN X INTERECEPT OF:
\n" ); document.write( "0=-2X+28
\n" ); document.write( "-2X=-28
\n" ); document.write( "X=-28/-2
\n" ); document.write( "X=14 OR (14,0)
\n" ); document.write( "THE LINE PERPENDICULAR WOULD HAVE A SLOPE=1/2 PASSING THROUGH (12,0)IS:
\n" ); document.write( "0=1/2*12+b
\n" ); document.write( "b=-6
\n" ); document.write( "Y=X/2-6 IS THE EQUATION OF THIS PERPENDICULAR LINE PASSING THROUGH (12,0) OR THE (GREEN LINE)
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-6%2C+15%2C+-10%2C+30%2C+y+=+-2x+%2B28%2C+y+=+x%2F2+-6%29+\"$ (graph 300x300 pixels, x from -6 to 15, y from -10 to 30, of TWO functions y = -2x +28 and y = x/2 -6). \n" ); document.write( "

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