document.write( "Question 121495: Can you help me solve the following problem. It is to Factor the polynomial completely.\r
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\n" ); document.write( "\n" ); document.write( "I really appriciate it. I am not getting this section at all.
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Algebra.Com's Answer #89145 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"125a%5E3+-+8b%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"+%285a%29%5E3+-+%282b%29%5E3+\".........use general rule to factor the difference of cubes: \"+highlight%28x%5E3-y%5E3=%28x+-+y%29%28x%5E2+%2B+xy+%2B+y%5E2%29%29+\".........\r
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\n" ); document.write( "\n" ); document.write( "\"+%285a+-+2b%29%28%285a%29%5E2+%2B+5a%28-+2b%29+%2B%28-+2b%29%5E2%29+\".........\r
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\n" ); document.write( "\n" ); document.write( "\"+%285a+-+2b%29%28%285a%29%5E2+-+10ab++%2B+%28-2b%29%5E2%29+\".........since the quadratic \r
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\n" ); document.write( "\n" ); document.write( "\"%28%285a%29%5E2+-+10ab++%2B+%28-2b%29%5E2%29\" cannot be factored further, your answer is:\r
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\n" ); document.write( "\n" ); document.write( "\"+highlight%28%285a+-+2b%29%28%285a%29%5E2+-+10ab++%2B+%28-2b%29%5E2%29%29+\".........
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