document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121444>Question 121444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An alloy weighing 20 lbs is 30% copper. How many pounds of another alloy, which is 80% copper must be added for the final alloy t be 60% copper.\r<BR>\n" );
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document.write( "could you please help me with the set up of the equation for this problem to help me solve it.\r<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89125 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89125\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An alloy weighing 20 lbs is 30% copper. How many pounds of another alloy, which is 80% copper must be added for the final alloy t be 60% copper. <BR>\n" );
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document.write( "Let x = amt of 80% copper alloy must be added:<BR>\n" );
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document.write( "The equation:<BR>\n" );
document.write( ".30(20) + .80(x) = .60(x+20) </SPAN>\n" );
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