document.write( "Question 121404This question is from textbook beginning and intermediate algebra
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document.write( ": 1/6(5s+3)=1/2(s+11)\r
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document.write( "1/6(2c-1)=1/3c-1/6 \n" );
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Algebra.Com's Answer #89076 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1/6(5s+3)=1/2(s+11) \n" ); document.write( "Multiply both sides by 6 to get: \n" ); document.write( "(5s+3) = 3(s+11) \n" ); document.write( "5s+15 = 3s+33 \n" ); document.write( "2s = 18 \n" ); document.write( "s = 9 \n" ); document.write( "================= \r \n" ); document.write( "\n" ); document.write( "1/6(2c-1)=(1/3)c-1/6 \n" ); document.write( "Multiply both sides by 6 to get: \n" ); document.write( "(2c-1) = 2c - 1 \n" ); document.write( "0=0 \n" ); document.write( "The equation is true for all Real values of \"c\". \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |