document.write( "Question 121396This question is from textbook algebra and trigonometry with analiytic geometry
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document.write( ": A consulting engineer's time is billed at $100 per hour, and her assistant's is billed at $20 per hour. A customer received a bill for $1200 for a certain job. If the assistant worked 3 hours less than the engineer, how much time did each bill on the job? \n" );
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Algebra.Com's Answer #89072 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 100X+20(X-3)=1200 \n" ); document.write( "100X+20X-60=1200 \n" ); document.write( "120X=1200+60 \n" ); document.write( "120X=1260 \n" ); document.write( "X=1260/120 \n" ); document.write( "X=10.5 HOURS WAS BILLED FOR THE ENGINEER OR: \n" ); document.write( "100*10.5=$1050 WAS THE ENGINEER'S BILL. \n" ); document.write( "20(10.5-3)=20*7.5=$150 WAS THE ASSISTANT'S BILL. \n" ); document.write( "PROOF \n" ); document.write( "100*10.5+20*7.5=1200 \n" ); document.write( "1050+150=1200 \n" ); document.write( "1200=1200 \n" ); document.write( " |