document.write( "Question 121306: There are two rectangular plots of land, A and B. The difference between the length and the width of A is 3 m. The length of A is 8 m more than that of B; the width of A is 5 m less than the width of B and the area of B is 250 m squared more than half the area of A. Find lengths and widths of A and B.\r
\n" ); document.write( "\n" ); document.write( "Formula given:
\n" ); document.write( "Area of B - 1/2 Area of A = 250 \n" ); document.write( "
Algebra.Com's Answer #89063 by jaymore(5)\"\" \"About 
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Let the dimensions of plot B be x and y
\n" ); document.write( "The dimensions of plot A will be x+8 and y-5
\n" ); document.write( "Difference in lengh n width of plot A
\n" ); document.write( "(x+8)-(y-5)=3
\n" ); document.write( "Solve to get x-y=-10 or x+10=y\r
\n" ); document.write( "\n" ); document.write( "Area of Plot A:
\n" ); document.write( "(x+8)(y-5)
\n" ); document.write( "Expand to get xy-5x+8y-40
\n" ); document.write( "Substitute x+10=y in the equation to get
\n" ); document.write( "Xsquared+13x+40\r
\n" ); document.write( "\n" ); document.write( "Area of Plot B:
\n" ); document.write( "xy=x(x+10)=Xsquared+10x\r
\n" ); document.write( "\n" ); document.write( "(Xsquared+10x)-1/2(Xsquared+13x+40)=250
\n" ); document.write( "Simplyfy to get Xsquared+7x-540=0
\n" ); document.write( "Solve quadratic equation
\n" ); document.write( "X=20 and y=x+10=20+10=30
\n" ); document.write( "Plot A:
\n" ); document.write( "Length=28 width=25
\n" ); document.write( "Plot B:
\n" ); document.write( "Length=20 width=30\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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