document.write( "Question 121266: r - 5 square root of r - 36 = 0\r
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Algebra.Com's Answer #89014 by Nate(3500)\"\" \"About 
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r - 5*sqrt(r - 36) = 0
\n" ); document.write( "r = 5*sqrt(r - 36)
\n" ); document.write( "r^2 = 25(r - 36)
\n" ); document.write( "r^2 = 25r - 900
\n" ); document.write( "r^2 - 25r + 900 = 0
\n" ); document.write( "r = (25 +- sqrt(625 - 3600))/2
\n" ); document.write( "r = (25 +- i*sqrt(2975))/2
\n" ); document.write( "r = (25 +- 5i*sqrt(119))/2
\n" ); document.write( "You may have to check those two answers, for one might be an exlusionary extraneous.
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