document.write( "Question 121237This question is from textbook beginning and intermediate algebra
\n" ); document.write( ": Could someone please show me how to solve this problem
\n" ); document.write( "x=e^-7.85 my teacher saids the answer is 3.90*10^-4 I can't figure out how she came up with that answer. By the way the -7.85 and the -4 are exponents, I couldn't get them to show up right. Thanks for helping. \n" ); document.write( "

Algebra.Com's Answer #89001 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
x = e^-7.85
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\n" ); document.write( "Find the nat log of both sides:
\n" ); document.write( "ln(x) = ln(e^-7.85)
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\n" ); document.write( "Use the log equivalent of exponents
\n" ); document.write( "ln(x) = -7..85*ln(e)
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\n" ); document.write( "We know nat log of e is 1 so we just have:
\n" ); document.write( "ln(x) = -7.85
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\n" ); document.write( "Find the anti log of -7.85, that's $\"e%5Ex\"$ on the calculator
\n" ); document.write( "x = 3.897519683 E -4 is the solution from my calc
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\n" ); document.write( "You can see that it could be written in scientific notation
\n" ); document.write( "x = 3.90*10^-4
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