document.write( "Question 121153: Here's my question:
\n" ); document.write( "One day, the temperature at 8:00 A.M. was 41 degrees Farenheight, and by 1:00 P.M. the temperature was 61 degrees Farenheight. What was the hourly rate of temperature change??
\n" ); document.write( "I got 4 degrees farenheight/hour. Thanks!!
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Algebra.Com's Answer #88990 by stanbon(75887)\"\" \"About 
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One day, the temperature at 8:00 A.M. was 41 degrees Farenheight, and by 1:00 P.M. the temperature was 61 degrees Farenheight. What was the hourly rate of temperature change??
\n" ); document.write( "I got 4 degrees farenheight/hour.
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\n" ); document.write( "You have two points: (8,41) and (13,61)
\n" ); document.write( "slope = (61-41)/(13-8) = 20/5 = 2 degrees/hr.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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