document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121154>Question 121154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let f(x)=x^3 -2. What is f(1/2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88962 by </B><A HREF=/tutors/aboutme.mpl?userid=Prithwis><B>Prithwis(166)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Prithwis><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.nriassociation.com/BeliveITorNOT/mittal70millionHouse.jpg valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find f(1/2) for f(x)=x^3 -2\r<BR>\n" );
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document.write( "f(1/2)=(1/2)^3 -2\r<BR>\n" );
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document.write( "=> f(1/2)=(1/8) -2    <BR>\n" );
document.write( "[Note: For (1/2)^3 just raise top and bottom to power of 3 and get 1/8]\r<BR>\n" );
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document.write( "=>f(1/2)= (1-16)/8\r<BR>\n" );
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document.write( "=>f(1/2)= (-15)/8\r<BR>\n" );
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document.write( "So, f(1/2)=(-15)/8 for when f(x)=x^3 -2 </SPAN>\n" );
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