document.write( "Question 121232: . (3 pts) A small area in front of a building is triangular in shape. The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region. \r
\n" );
document.write( "\n" );
document.write( "37= (½ * x) + (x-3)
\n" );
document.write( "37= 1/2x + (x-3)
\n" );
document.write( "39.5=2x
\n" );
document.write( "X=19.75
\n" );
document.write( "1st side= 19.75 meter
\n" );
document.write( "2nd side= 0.5 * 19.75 = 9.875 meters
\n" );
document.write( "3rd side= 19.75-3= 16.75 meters
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #88954 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A small area in front of a building is triangular in shape. The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region. \n" ); document.write( "--------------- \n" ); document.write( "1st side: x meters \n" ); document.write( "2nd side: x/2 meters \n" ); document.write( "3rd side: x-3 meters \n" ); document.write( "------------------------ \n" ); document.write( "EQUATION: \n" ); document.write( "x + x/2 + x-3 = 37 \n" ); document.write( "2x + x + 2x-6 = 74 \n" ); document.write( "5x = 80 \n" ); document.write( "x = 16 meters \n" ); document.write( "x/2 = 8 meters \n" ); document.write( "x-2 = 13 meters \n" ); document.write( "--------- \n" ); document.write( "Checking \n" ); document.write( "16+8+13 = 37 meters \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |