document.write( "Question 121232: . (3 pts) A small area in front of a building is triangular in shape. The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region. \r
\n" ); document.write( "\n" ); document.write( "37= (½ * x) + (x-3)
\n" ); document.write( "37= 1/2x + (x-3)
\n" ); document.write( "39.5=2x
\n" ); document.write( "X=19.75
\n" ); document.write( "1st side= 19.75 meter
\n" ); document.write( "2nd side= 0.5 * 19.75 = 9.875 meters
\n" ); document.write( "3rd side= 19.75-3= 16.75 meters
\n" ); document.write( "
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Algebra.Com's Answer #88954 by stanbon(75887)\"\" \"About 
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A small area in front of a building is triangular in shape. The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region.
\n" ); document.write( "---------------
\n" ); document.write( "1st side: x meters
\n" ); document.write( "2nd side: x/2 meters
\n" ); document.write( "3rd side: x-3 meters
\n" ); document.write( "------------------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "x + x/2 + x-3 = 37
\n" ); document.write( "2x + x + 2x-6 = 74
\n" ); document.write( "5x = 80
\n" ); document.write( "x = 16 meters
\n" ); document.write( "x/2 = 8 meters
\n" ); document.write( "x-2 = 13 meters
\n" ); document.write( "---------
\n" ); document.write( "Checking
\n" ); document.write( "16+8+13 = 37 meters
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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