document.write( "Question 121224This question is from textbook Beginning and Intermediate Algebra
\n" ); document.write( ": Please help! I need to be able to do this type of problem for my Chemistry II class and its been a little while since I've had this type of math...\r
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\n" ); document.write( "\n" ); document.write( "((1.8*10^-3)/(9.0*10^-4))^X = ((6.4*10^-1)/(8.0*10^-2))\r
\n" ); document.write( "\n" ); document.write( "In case this is confusing the way it is written out, on the left side of the equation the entire division problem is raised to the power of x. \r
\n" ); document.write( "\n" ); document.write( "I know this is a quadratic problem, where I have to get to ax^2 + bx + c = 0, then go on and plug the numbers into the quadratic formula. I'm having trouble getting it into this form though. The professor said that the final answer is 3, but I havent been able to get that on my own. I'd appreciate if anyone could give me a step-by-step explanation of how to do this, so that I can go on to do the other similar problems on my own. Thanks a lot!
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Algebra.Com's Answer #88952 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Well in this case, you do not need the quadratic formula.\r
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\n" ); document.write( "\n" ); document.write( " Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%280.2%2A10%29%5Ex+=+%28%286.4%2A10%5E-1%29%2F%288.0%2A10%5E-2%29%29+\" Divide \"1.8%2F9.0\" to get \"0.2\". Also, divide \"10%5E-3%2F10%5E-4\" to get \"10%5E-3%2F10%5E-4=10%5E%28-3-%28-4%29%29=10%5E%28-3%2B4%29=10%5E1=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+%28%286.4%2A10%5E-1%29%2F%288.0%2A10%5E-2%29%29+\" Multiply 0.2 and 10 to get 2\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+%280.8%2A10%29+\" Divide \"6.4%2F8.0\" to get \"0.8\". Also, divide \"10%5E-1%2F10%5E-2\" to get \"10%5E-1%2F10%5E-2=10%5E%28-1-%28-2%29%29=10%5E%28-1%2B2%29=10%5E1=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+8+\" Multiply 0.8 and 10 to get 8\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%282%5Ex%29%29+=+log%2810%2C%288%29%29+\" Take the log of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Alog%2810%2C%282%29%29+=+log%2810%2C%288%29%29+\" Rewrite the left side using the identity \"log%28b%2Cx%5Ey%29=y%2Alog%28b%2Cx%29\"}\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+log%2810%2C%288%29%29%2Flog%2810%2C%282%29%29+\" Divide both sides by \"log%2810%2C%282%29%29\" to isolate x\r
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\n" ); document.write( "\n" ); document.write( "So after using a calculator, we get this:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+3+\" \r
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\n" ); document.write( "\n" ); document.write( "note: you could also ask yourself: 2 to what power equals 8? Since \"2%5E3=8\" the answer is \"x=3\"
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