document.write( "Question 121224This question is from textbook Beginning and Intermediate Algebra
\n" ); document.write( ": Please help! I need to be able to do this type of problem for my Chemistry II class and its been a little while since I've had this type of math...\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "((1.8*10^-3)/(9.0*10^-4))^X = ((6.4*10^-1)/(8.0*10^-2))\r
\n" ); document.write( "\n" ); document.write( "In case this is confusing the way it is written out, on the left side of the equation the entire division problem is raised to the power of x. \r
\n" ); document.write( "\n" ); document.write( "I know this is a quadratic problem, where I have to get to ax^2 + bx + c = 0, then go on and plug the numbers into the quadratic formula. I'm having trouble getting it into this form though. The professor said that the final answer is 3, but I havent been able to get that on my own. I'd appreciate if anyone could give me a step-by-step explanation of how to do this, so that I can go on to do the other similar problems on my own. Thanks a lot!
\n" ); document.write( "

Algebra.Com's Answer #88951 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
this is not a quadratic problem, it is exponents/logarithms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "performing the operations in the parentheses gives (2)^X=(8)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2 cubed is 8, so X=3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "for future reference (in case the numbers are not so straight forward)
\n" ); document.write( "__ taking the log gives X(log(2))=log(8), so X=(log(2))/log(8)
\n" ); document.write( "
\n" );