document.write( "Question 121208: Solve the equation. w^3+5w^2-w=5 \n" ); document.write( "

Algebra.Com's Answer #88934 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for w:
\n" ); document.write( " $\"w%5E3%2B5W%5E2-w+=+5\"$ First, subtract 5 from both sides.
\n" ); document.write( " $\"w%5E3%2B5w%5E2-w-5+=+0\"$ Then factor the left side.
\n" ); document.write( " $\"%28w%5E2-1%29%28w%2B5%29+=+0\"$ Apply the zero product principle.
\n" ); document.write( " $\"w%5E2-1+=+0\"$ or $\"w%2B5+=+0\"$
\n" ); document.write( "If $\"w%5E2-1+=+0\"$ then $\"w%5E2+=+1\"$ so $\"w+=+1\"$ or $\"w+=+-1\"$
\n" ); document.write( "If $\"w%2B5+=+0\"$ then $\"w+=+-5\"$
\n" ); document.write( "The solutions are:
\n" ); document.write( " $\"w+=+1\"$
\n" ); document.write( " $\"w+=+-1\"$
\n" ); document.write( " $\"w+=+-5\"$ \n" ); document.write( "

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