document.write( "Question 121194: I have this problem to do in my math end of term exam revision. I do not understand how to work it. \r
\n" ); document.write( "\n" ); document.write( "The problem is: in what year is the baseball card worth 20$? and the equation is: V(T)= 4.75(1.12)^t ...t=0 is year 1980. \r
\n" ); document.write( "\n" ); document.write( "Do I try different years for the fun of it or is there a way to calculate it?\r
\n" ); document.write( "\n" ); document.write( "Thanks for the help! \n" ); document.write( "
Algebra.Com's Answer #88924 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The problem is: in what year is the baseball card worth 20$? and the equation is: V(T)= 4.75(1.12)^t ...t=0 is year 1980.
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\n" ); document.write( "Let V(T) be $20 and solve for \"t\":
\n" ); document.write( "20 = 4.75(1.12)t
\n" ); document.write( "1.12^t = 4.2105
\n" ); document.write( "Take the log of both sides to get:
\n" ); document.write( "t*log(1.12) = log 4.2105
\n" ); document.write( "t = [log4.2105]/[log(1.12)]
\n" ); document.write( "t = 12.6851 years
\n" ); document.write( "-------------------------
\n" ); document.write( "If t=0 is 1980 you add 12.6851 years and you are
\n" ); document.write( "in the year 1993.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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